Question

gud morning ❤❤....,...........Sulphide ion reacts with solid sulphur
s-(aq) +S(s) = 8- (aq); k, = 10
s?- (aq) + 2S(s) = S(aq): Ky = 130
The equilibrium constant for the formation of S,2-(ag) from S, (aq) and sulphur is​

Answer 1

The chemical equilibria representing the reaction of sulfide ion with solid sulfur is,

Equilibrium -1 :S^-2(aq)+ S(s)<------>S2^2- (aq) K1= 10

Equilibrium -2 :S^2- (aq) + 2S <-----> S3^2- K2= 130

The above equilibria can be reaaranged to give the new equilibrium reaction for the formation of from and sulfur,

Reversing equilibrium -1: S2^2- <-----> S^2- + S K= 1/K1= 1/10 = 0.1

Adding equilbrium 2: S^2- + 2S <-----> S3^2- K2=130

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Net equilibrium : S^2- + S <-------> S3^2-. Knet= 1/K1 * K2

Therefore the equilibrium constant for the given equilibrium = 1/10*130=13

Answer 2

Hey refer to the attachment