Question

Gunpowder contains 75% nitre 10% sulphur
find the amount of gunpowder which carries
9kg nitre. What amount of gunponder would contain
2.5 kg sulphur​

Answer 1

Step-by-step explanation:

Let Amount of Gun Powder be of 100gm

so Acc.to composition 75% nitre of 100 gm will be 75 gm.

so 75 gm of nitre️ ➡️100 gm

9×1000 gm ➡️ ?

Amount of Gun powder =

$\frac{(100 \times 9 \times 1000)}{75}$

= 12 ×10^3 gm

=12 kg

Acc.to composition of sulphur 10% of 100 gm =10 gm

10gm➡️100gm

2.5×1000➡️?

Amount of Gun Powder =

$\frac{(100 \times 2.5 \times 1000)}{10}$

=25×10^3 gm

=25 kg