Math, asked by mjk77, 1 year ago

Gunpowder contains 75℅ nitre and 10℅sulphur.Find the amount of gunpowder which carries 9kg nitre. What amount of gunpowder would contain 2.5kg sulphur???

Answers

Answered by heeman7831
10
12kg gunpowder which contain 9kg nitre and
25kg gunpowder which contain 2.5kg sulphur
Answered by Muskan1101
48
Here's your answer!!

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Let x kg be the gunpowder which contain 9kg nitre.

So,

A/q

 =  > 75\% \: of \: x = 9

 =  >  \frac{75}{100} x = 9

 =  > x =  \frac{9  \times 100}{75}

 =  > x = 12kg

Hence,12 kg of gunpowder carry 9kg nitre.


Now,

Let y kg gunpowder contain 2.5 kg of Sulphur.

A/q

 =  > 10\% \: of \: y \:  = 2.5

 =  >  \frac{10}{100}y = 2.5

 =  > y =  \frac{2.5  \times 100}{10}

 =  > y = 25

Hence,

25kg of gunpowder carries 2.5 kg Sulphur.

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Hope it helps you!! :)

mjk77: Thank you very much for your help.It really helped me a lot... Thank you again....
heeman7831: Your welcome
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