guys do this physics question as you can as......,.............A particle is projected up into air with a speed of 20m/s at an angle of projection 30°.What is the maximum height reached by it?
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Time = -40 / -g = 4 second? I think?
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The horizontal component of “v” v cos 60 remains the same as the horizontal component of initial velocity 20 cos 30.
Hence v = 20 (cos 30 ) / ( cos 60) = 20 tan 60.= 34.64 m/s
Vertical component of “v” is - v sin 60 = - 30 m/s. Minus to denote downward direction.
Change in velocity in the vertical direction is -30 -20 sin 30 = -40 m/ s.
Time = -40 / -g = 4 second.