Question

guys help me.....

expand (a/2 - b + c)^2
$( \frac{a}{2} - b + c) {}^{2}$
​

Answer 1

SoluTion

$\implies (a - 2b - 3c)^{2}\\\\\implies {(a) + (- 2b) + (-3c)}^{2}$

We know that,

$\tt {(a+b+c)^{2} = a^{2}+b^{2} + c^{2} + 2ab + 2bc + 2ac}\\\\\implies \sf {(a)^{2} + (-2b)^{2} + (-3c)^{2} + 2 \times a \times (-2b) + 2 \times (-2b) \times (-3c) + 2 \times (-3c) \times (a)}\\\\\implies \sf {a^{2} + 4b^{2} + 9c^{2} -4ab + 12bc - 6ac}$

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Answer 2

Answer:

The answer is :

$\frac{a^{2} }{4} + {b}^{2} + {c}^{2} - ab - 2bc + ca$

Step-by-step explanation:

$( \frac{a}{2} - b + c)^{2} \\ = ( \frac{a}{2})^{2} + ( - b)^{2} + {c}^{2} + 2 \times \frac{a}{2} \times ( - b) + 2 \times ( - b) \times c + 2 \times c \times \frac{a}{2} \\ = \frac{ {a}^{2} }{4} + {b}^{2} + {c}^{2} - ab - 2bc + ca$

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