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The curve cuts x-axis at x=0 & x=2
The area bounded by the curve with x-axis and x=0,x=2 is integral 0 to2 2x-xv2
=xv2-xv3 /3 between 0&2
=(4-8/3)=4/3
The area bounded by the curve with x-axis and x=0,x=2 is integral 0 to2 2x-xv2
=xv2-xv3 /3 between 0&2
=(4-8/3)=4/3
why the curve will cut the x axis at o and 2 dear
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