Math, asked by prishaayoyo, 8 months ago

Guys help please
this question is very tough if you help mee then I will mark you the brainliest ​

Attachments:

Answers

Answered by amitsnh
1

Answer:

(x^20y^-10z^5)^(1/5) ÷ (x^3/y^3)

(x^20)^(1/5)*(y^-10)^(1/5)*(z^5)^(1/5) * (y^3/x^3)

x^(20*1/5) y^(-10*1/5) z^(5*1/5) * y^3*x^-3

x^4 y^-2 z^1 y^3 x^-3

x^(4-3) y^(-2+3) z

XYZ ans

Answered by zheii
0

Answer:

\sqrt[5]{x^{20}y^{-10}z^{5} } ÷  \frac{x^{3}}{y^{3} }  = xyz

Step-by-step explanation:

\sqrt[5]{x^{20}y^{-10}z^{5} } ÷  \frac{x^{3}}{y^{3} } = \sqrt[5]{x^{20}y^{-10}z^{5} } ×   \frac{y^{3}}{x^{3} }

                           = \sqrt[5]{x^{20} } × \sqrt[5]{y^{-10} } × \sqrt[5]{z^{5} }  ×   \frac{y^{3}}{x^{3} }

                           = x^{\frac{20}{5} } × y^{\frac{-10}{5} } × z^{\frac{5}{5} } ×   \frac{y^{3}}{x^{3} }                      

                           = x^{4} × y^{-2} × z × y^{3} ÷ x^{3}

                           = x^{4-3} × y^{-2 + 3} × z

                           = xyz

Similar questions
Math, 4 months ago