Question

.......Guys help pls❤​

Answer 1

HEYA GA ❤

# CIRCULAR MOTION..

TQ ^_^

Answer 2

Answer: (3). The speed of the particle is 5.69 m/s.

Explanation:

Given that,

The acceleration$a = 15m/s^2$

Radius R = 2.5 m

We know that,

The radial acceleration is

$a\ cos \theta= \dfrac{v^2}{r}$

$15\times cos30^{0}= \dfrac{v^2}{r}$

$15\times\dfrac{\sqrt{3}}{2}= \dfrac{v^2}{2.5}$

$v^2=\dfrac{15\times\sqrt{3}\times2.5}{2}$

$v^2= 32.48\ m/s$

$v = 5.7 \ m/s$

Hence, The speed of the particle is 5.7 m/s.