Question

guys iska solution dijiye plz

Answer 1

(12)

Given f(x) = ax^2 - 3(a - 1) * x - 1.

Given that 2 is  a zero of the polynomial.

if 2 is a zero of the polynomial, then f(2) = 0

⇒ a(2)^2 - 3(a - 1) * 2 - 1 = 0

⇒ 4a - (3a + 3) * 2 - 1 = 0

⇒ 4a - 6a - 5 = 0

⇒ -2a = 5 = 0

⇒ -2a = -5

⇒ a = 5/2.

Therefore, the answer is 5/2  ---- Option (A)

Hope it helps!

Answer 2

According to remainder theorem,
$f(x) = ax {}^{2} - 3(a - 1)x - 1$
Inserting the value of (x) as 2
$f(2) = a \times 2 {}^{2} - 3(a - 1)2- 1 \\ = > 4a - 6(a - 1) - 1 = 0 \\ = > 4a - 6a - 5 = 0$
=>(-2)a=5
=>a = (- 5)/2
So, the correct answer is option C.

Hope this will help you.

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