Question

Guys PL help me solve!!!!!!!!!!!!; What's the solution for:-
(a+b+c)²+(a-b+c)²(a+b-c)²

Answer 1

Answer:

Step-by-step explanation:

(a+b+c)² =a²+b²+c²+2ab+2bc+2ca

(a-b+c)² =a²+b²+c²-2ab-2bc+2ca

(a + b - c)2 = a2 + b2 + c2 + 2ab – 2bc - 2ca

after solving all

3(a^2 + b^2 + c^2 ) + 2ab - 2bc + 2ca

MARK IT THE BRIANLEIST

Answer 2

Answer:

$\red{\bf{3( {a}^{2} + {b}^{2} + {c}^{2} ) + 2ab - 2bc + 2ca}}$

Step-by-step explanation:

We know that,

$\bf{ {(a + b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ca}$

And,

$\bf{ \green{ {(a - b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} - 2ab - 2bc + 2ca}}$

Ans also,

$\bf{\pink{{(a + b - c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2ab - 2bc - 2ca}}$

Hence,

We required :-

$\bf{{(a + b + c)}^{2} + {(a - b + c)}^{2} {(a+b-c)}^{2} }$

Adding these then we get required solution.

${\bf{3( {a}^{2} + {b}^{2} + {c}^{2} ) + 2ab - 2bc + 2ca}}$