guys please answer this question.
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Given :
ρ(oil) = 0.9 g/cc
ρ(mercury) = 13.6 g/cc
ρ (CCl₄) = 1.6 g/cc
Take a reference level at point D.
At this reference level pressure in both the limbs must be equal,
⇒ [ ρ (mercury) x g x (20-h) ] + [ ρ (oil) x g x h ] = ρ (CCl₄) x g x 20
⇒ 13.6 x g x (20-h) + 0.9 x g x h = 1.6 x g x 20
⇒ 0.9h + 13.6(20-h) = 1.6 x 20
⇒ 272 - 12.7h = 32
⇒ h = (272 - 32) / 12.7
∴ h = 18.897 cm.
HOPE THIS HELPS YOU !! : )
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