guys please answer this question as soon as possible
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This is a question based on rate of reaction.
Rate of reaction is given by
Rate r = -[∆N2]/∆t = -1/3[∆H2]∆t = +1/2[∆NH3]/∆t
Rate of formation of NH3 = [∆NH3]/∆t
= 2.4×10^-2 M/min
So, rate of reaction = 1/2 × 2.4×10^-2
= 1.2 × 10^-2 M/min
Rate of reaction of N2 = 1.2×10^-2 M/min (same concept)
Rate of reaction of H2 = 3/2× 2.4×10^-2
= 3.6× 10^-2 M/min
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