Question

guys please answer this question. I'll mark as brainliest answer fot the first answer. no googling and no brainly and also full explanation with every single step. picture is best​.

Answer 1

Answer:

a=0.125m/s

distance=900 m

Explanation:

Given that,

Intial velocity u=0m/s

Final velocity v=54km/h=54× 5/18 =15m/s

Time t=2min=120s

Now, put the value in equation of motion

The acceleration is

v=u+at

a= v−u/t

a= 15−0/120

a=0.125m/s ^2

Now, again from equation of motion

The distance is

s=ut+ 1/2at^2

s=0+ 1/2×0.125×120×120

s=900m

Hence, the acceleration is 0.125m/s^2

and distance is 900m

sorry but i cant take picture because it will be very difficult to understand my handwriting