Question

Guys Please help me......... ​

Answer 1

answer 1

Explanation:

2) We have,

f(x) = x2-√2x -12

Now, put f(x) = 0

x2-√2x –12 = 0

x2 - 3√2x + 2√2x – 12 = 0

x(x - 3√2) + 2√2(x - 3√2) = 0

(x - 3√2)(x + 2√2) = 0

x - 3√2 = 0 or x + 2√2 = 0

x = 3√2 or x = -2√2

So, the zeros of given polynomial are 3√2 and -2√2.

Answer 2

Answer:

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happy dipawali

Explanation:

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