Guys! Please help me prove this one!
Attachments:
Answers
Answered by
2
it is given that 2^x=3^y=6^z then it must be a constant.
2^x=3^y=6^z=k where k is a constant.
take the numbers separately to be equal with the constant.
2^x=k
2=k^1/x ..............(i)
3^y=k
3=k^1/y ................(ii)
6^z=k
6=k^1/z ................(iv)
we know that, 6=2*3
putting the values from the equations.
k^1/z=k^1/x*k^1/y
k^1/z=k^1/x+1/y
since the bases are same the powers are equal.
so 1/z=1/x+1/y
2^x=3^y=6^z=k where k is a constant.
take the numbers separately to be equal with the constant.
2^x=k
2=k^1/x ..............(i)
3^y=k
3=k^1/y ................(ii)
6^z=k
6=k^1/z ................(iv)
we know that, 6=2*3
putting the values from the equations.
k^1/z=k^1/x*k^1/y
k^1/z=k^1/x+1/y
since the bases are same the powers are equal.
so 1/z=1/x+1/y
shriprateek:
please mark it as brainliest.............
very good answer......
appreciable.......
Similar questions