guys please help me question is in attachment.rd sharma class 10 session 2020-21.
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Explanation:
Consider 1+tan2theta/1+cot2theta
=sec2theta/cosec2theta
=1/cos2theta × sin2theta
=tan2theta
Next (1-tan theta/1-cot theta)2
=(1-tan theta/1-1/tan theta)2
=(1-tan theta)2/(tan theta-1/tan theta)2
=[tan theta(1- tan theta)/tan theta-1]2
=[-tan theta (tan theta-1)/tan theta-1]2
=tan2 theta
From above it is clear that both = tan2 theta
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