Question

guys please help me to solve this...​

Answer 1

Answer:

it's not the same question but agr is method se kroge toh answer mil jayega

hope it will help you buddy

Answer 2

Answer:

The velocity of water flowing from open tap is 10 m/s.

Explanation:

➣ Given that:

• Pressure of water in the waterpipe when tap is opened is 2 × 10⁵ N/m².

• Pressure of water in the waterpipe when tap is closed is 2.5 × 10⁵ N/m².

➣ To find:

Velocity of water flowing from open tap.

➣ Solution:

We know that,

ΔP = 1/2pv²

➪ (0.5 × 10⁵) = 1/2 × 1000 × v²

➪ 50,000 = 500 × v²

➪ 50,000/500 = v²

➪ v² = 100

➪ v = √100 = 10 m/s.