Question

0.9 g impure calcium carbonate neutralizes a solution containing 0.735g H2So4. Calculate purity percent of calcium Carbonate.​

Answer 1

Explanation:

Answer: 80% of the calcium carbonate is pure.

Explanation: Decomposition of calcium carbonate is written as:

Molar mass of  = 100g/mol

Molar mass of CaO = 56g/mol

Let the pure sample of  = y grams.

Mass of CaO produced after decomposition = 22.4 grams

If 100g of pure sample of  produces 56g of CaO, then "y" gram of pure sample of  produces 22.4 grams of CaO.

Calculating for y, we get

y = 40 grams

% purity of  can be calculated by:

Putting the values, we get

% purity of  in the sample = 80%