Question

Is it possible to have a regular polygon whose each
exterior angle is
i) 25°
ii) 135°
iii) 72°
If yes then find the number of sides in the regular polygon,
if not, give reason

pls tell guys..I will mark the first one who gave correct answer brainlist but dont write useless n unexpected answers​

Answer 1

Answer:

be a convex polygon of n sides, whose sides have been produced in the ... Find the number of sides of a regular polygon if each of its exterior angles

Answer 2

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Is it possible to have a regular polygon whose each exterior angle is i) 25° , ii) 135° , iii) 72°

$\huge\rm { ☆_!! Answer !_! ☆}$

As we know , $\tt number \: of \: sides \: of \: a \: polygon = \dfrac{360°}{each \: exterior \: angle}$

(a) Measure of each exterior angle = 25°

Number of sides of given polygon

= 360 ° ÷ 25 ° = 14.4

⇢ Since, answer is not a whole number, so, a regular polygon with measure of each exterior angle as 25⁰ is not possible.

∴ Answer = no

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(b) Measure of each exterior angle =135°

Number of sides of given polygon

= 360 ° ÷ 135° = 2.6667

⇢Since, answer is not a whole number, so, a regular polygon with measure of each exterior angle as 135⁰ is not possible.

∴ Answer = no

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(c) Measure of each exterior angle = 72°

Number of sides of given polygon

= 360 ° ÷ 72° = 5

⇢Since, answer is a whole number, so, a regular polygon with measure of each exterior angle as 72⁰ is possible.

∴ Answer = yes

✭ Numbers of sides = 360 ° ÷ 72° = 5 sides