Question

Prove that cosA.cosecA-sinA.secC by cosA+sinA=cosecC-secA​

Answer 1

Answer:

hence proved

Step-by-step explanation:

LHS=

cosA+sinA

cosAcosecA−sinAsecA

=

sinAcosA(cosA+sinA)

cos

2

A−sin

2

A

=

sinAcosA(cosA+sinA)

(cosA−sinA)(cosA+sinA)

=

sinAcosA

cosA−sinA

=

sinA

1

−

cosA

1

=cosecA−secA

=RHS

Hence proved

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