Prove that cosA.cosecA-sinA.secC by cosA+sinA=cosecC-secA
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Answer:
hence proved
Step-by-step explanation:
LHS=
cosA+sinA
cosAcosecA−sinAsecA
=
sinAcosA(cosA+sinA)
cos
2
A−sin
2
A
=
sinAcosA(cosA+sinA)
(cosA−sinA)(cosA+sinA)
=
sinAcosA
cosA−sinA
=
sinA
1
−
cosA
1
=cosecA−secA
=RHS
Hence proved
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