Question

guys please help me with this question and whoever will give me the answer I will mark them as brainlist but I don't want any useless answer​

Answer 1

Answer:

As the scale is uniform, so the weight will be balanced at mid point i.e. 50 cm of the scale.  

Let, M be the mass of the meter scale.

Using principle of moments, for equilibrium,  sum of moment of force on left side of knife edge is equal to sum of moment of force on right side.

So, (70−50)Mg=(94−70)0.05g    (as moment of force = force × perpendicular distance from fulcrum)

or M=0.06kg  

Explanation:

I hope it will help you !