guys please please answer it
Answers
Answer:
Q.1)
a. x = (-8/5) or (-1.6)
b. x = (-5)
c. y = (7/3)
d. y = (-8)
Q.2)
Hari's present age = 20 yrs.
Harry's present age = 28 yrs.
Step-by-step explanation:
Q.1)
a. We have,
(x/3) + 1 = (7/15)
(x/3) = (7/15) - 1
Taking LCM = 15
(x/3) = (7/15) - (15/15)
(x/3) = (7 - 15)/15
(x/3) = (-8/15)
x = 3 × (-8/15)
x = (-8/5)
Dividing it we get,
x = (-1.6)
Hence,
x = (-8/5) or (-1.6)
b. We have,
10x + 7 = 3x - 28
10x - 3x = -28 - 7
7x = -35
x = (-35)/7
x = (-5)
Hence,
x = (-5)
c. We have,
2y + (5/3) = (26/3) - y
2y + y = (26/3) - (5/3)
3y = (26 - 5)/3
3y = 21/3
3y = 7
y = (7/3)
Hence,
y = (7/3)
d. We have,
(3y + 4)/(2 - 6y) = (-2/5)
Cross multiplying we get,
5(3y + 4) = (-2)(2 - 6y)
15y + 20 = (-4) + 12y
15y - 12y = (-4) - 20
3y = (-24)
y = (-24)/3
y = (-8)
Hence,
y = (-8)
Q.2)
Let the present age of Hari be 5x
Let the present age of Harry be 7x
After 4 yrs.
Hari's age = 5x + 4
Harry's age = 7x + 4
But, according to the Question,
(5x + 4) : (7x + 4) :: 3 : 4
We know that,
Product of extremes = Product of means
4(5x + 4) = 3(7x + 4)
20x + 16 = 21x + 12
21x - 20x = 16 - 12
x = 4
Hence,
Hari's present age = 5(4) = 20 yrs.
Harry's present age = 7(4) = 28 yrs.
Hope it helped and believing you understood it........All the best