Math, asked by gdeepakbharadwaj2009, 1 month ago

Guys please put the correct answer for the 3 questions please put the answer fast​

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Answered by ginogladson1
3

Answer:- 1. Prime factorization of 4851

4851 = 3×3×7×7×11

By grouping the prime factors

= (3×3) × (7×7) × 11

11 is left out

Therefore, the smallest number by which 4851 must be multiplied so that the product becomes a perfect square is 11

2. Prime factorization of 28812

28812 = 2×2×3×7×7×7×7

By grouping the prime factors

= (2×2) × 3 × (7×7) × (7×7)

3 is left out

Therefore, the smallest number by which 28812 must be divided so that the quotient becomes a perfect square is 3

3. Prime factorization of 1152

1152 = 2×2×2×2×2×2×2×3×3

By grouping the prime factors

= (2×2) × (2×2) × (2×2) × (3×3) × 2

Therefore, the smallest number by which 1152 must be divided so that the quotient becomes a perfect square is 2.

The number after division, 1152/2 = 576

Prime factors for 576 = 2×2×2×2×2×2×3×3

By grouping the prime factors

= (2×2) × (2×2) × (2×2) × (3×3)

= (2×2×2×3) × (2×2×2×3)

= 242

Therefore, the resulting number is square of 24.

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