Question

guys please solve 12 and 13 .

Answer 1

Hi friend,

12) a)Length=8m
Breadth=6m
Height=5m

It is said to distemper 4 walls so we will find CSA(curved surface area).

CSA of a cuboide=2*h(l+b)
=2*5(8+6)
=10*14
=140 m^2

Cost of distempering 1m^2=₹30
Cost of distempering 140m^2=140*30
=₹4200

b) Length of the roof=8m
Breadth=6m
Area=L*B
=8*6
=48m^2

Cost of white wash the roof per m^2=₹20
Cost of white washing 48m^2=48*20
=₹960

13) a)Find CSA.
Length=4.8m
Breadth=3.2m
Height=3m
CSA=2*h(l+b)
=2*3(4.8+3.2)
=6*8
=48m^2

Length of door=1m
Breadth of door=75m
Area of door=l*b
=1*75
=75m^2

Length of the window=1m
Breadth of the window=2m
Area of the window=l*b
=1*2
=2m^2

Total area=48+75+2
=125m^2

b)Find CSA.
And we already got to know that the CSA is 48m^2 as we already solved in a) part.

c)Walls(4) we know CSA is 48m^2.

Cost of distempering 1m^2=₹40
Cost of distempering 48m^2
=48*40
=₹1920

Cost of polishing the door and window=₹60
Total area of doors and windows=75+2
=77m^2
Cost of polishing them=77*60
=₹4620.

Hope it helped you........................