guys please solve 16 , iii .
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its like this
area of internal rect.=50 ×36 cm sq
=1800cm sq
L of outer rect. =50+5+5
=60cm
b of outer circle =36+5+5
=46 cm
area of outer circle =60×46cm sq
=2760cm sq
area of shaded portion =2760-1800cm sq
=960cm sq
area of internal rect.=50 ×36 cm sq
=1800cm sq
L of outer rect. =50+5+5
=60cm
b of outer circle =36+5+5
=46 cm
area of outer circle =60×46cm sq
=2760cm sq
area of shaded portion =2760-1800cm sq
=960cm sq
narendremodi2:
did u understand???
yes
Answered by
1
area of external rectangle - area of internal rectangle
eternal length =60 cm
external width =46cm
area of external =2760
area of shaded portion = 960cm Sq.
eternal length =60 cm
external width =46cm
area of external =2760
area of shaded portion = 960cm Sq.
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