Guys, please solve question 13.
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7
HELLO DEAR,
By Euclid's division Lemma on 92690 and 7378
For every point of integers a and b there exist unique integer q and r such that a = bq + r
where 0 ≤ r < b
So here and a > b
a = 92690 And b = 7378 ,So that
92690 = 7378 × 13 + 4154
7378 = 4154 × 1 + 3224
4154 = 3224 × 1 + 930
3224 = 930 × 3 + 434
934 = 434 × 2 + 62
434 = 62 × 7 + 0
Here r = 0 So H.C.F. of 92690 and 7378 is 62
Now apply Euclid division lemma on 62 and 7161
Here a = 7161 and b = 62 ,So that a> b
7161 = 62 × 115 + 31
I HOPE ITS HELP YOU DEAR TO
, THANKS
By Euclid's division Lemma on 92690 and 7378
For every point of integers a and b there exist unique integer q and r such that a = bq + r
where 0 ≤ r < b
So here and a > b
a = 92690 And b = 7378 ,So that
92690 = 7378 × 13 + 4154
7378 = 4154 × 1 + 3224
4154 = 3224 × 1 + 930
3224 = 930 × 3 + 434
934 = 434 × 2 + 62
434 = 62 × 7 + 0
Here r = 0 So H.C.F. of 92690 and 7378 is 62
Now apply Euclid division lemma on 62 and 7161
Here a = 7161 and b = 62 ,So that a> b
7161 = 62 × 115 + 31
I HOPE ITS HELP YOU DEAR TO
, THANKS
Answered by
3
Answer:
hcf =====62..............?..
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