Guys please solve question no 19 please
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Let a triangle ∆ABC
H(Hypotenuse) = 13cm
P(Perpendicular) = 12cm
B(Base)= ?
ACC. to Pythagoras theorem-
H²=B²+P²
=> B²= H²-P²
B = √13²-12²
B = √25
B = 5cm
Area of ∆ABC = 1/2 × B × P
= 1/2 × 5 × 12
= 60/2
= 30cm²
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