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1
if ∆ ABC ~ ∆ DEF ,
THEN ,
AB/DE = AC/DF = BC/ EF
( 2x - 1 ) / 18 = 3x/ 6x = (2x+2)/(3x+9)
2x-1 /18 = 1/2
2x-1 = 9
2x= 10
X= 5
so ,
AB = 2X-1 = 9
DE = 18
AC = 3X = 15
DF= 6X= 30
BC = 2X+2 = 12
EF= 3X+9= 24
Answered by
1
Answer:
Given, △ABC∼△DEF
Therefore,
DE
AB
=
EF
BC
=
FD
CA
So,
18
2x−1
=
3x+9
2x+2
=
6x
3x
Now taking
18
2x−1
=
6x
3x
, we have
18
2x−1
or 4x−2=18 or x=5
Therefore, AB=2×5−1=9,
BC=2×5+2=12,CA=3×5=15,
DE=18,EF=3×5+9=24
and FD=6×5=30
Hence,
AB=9cm,BC=12cm,CA=15cm,DE=18cm,EF=24cm and FD=30cm
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