Math, asked by snehasshekhar, 2 months ago


GUYS PLEASE TELL THIS QUESTION WITH FULL EXPLANATION.

❌❌ NO SPAMMING ❌❌​

Attachments:

Answers

Answered by anu1096
1

if ∆ ABC ~ ∆ DEF ,

THEN ,

AB/DE = AC/DF = BC/ EF

( 2x - 1 ) / 18 = 3x/ 6x = (2x+2)/(3x+9)

2x-1 /18 = 1/2

2x-1 = 9

2x= 10

X= 5

so ,

AB = 2X-1 = 9

DE = 18

AC = 3X = 15

DF= 6X= 30

BC = 2X+2 = 12

EF= 3X+9= 24

Answered by Aditi0905
1

Answer:

Given, △ABC∼△DEF

Therefore,

DE

AB

=

EF

BC

=

FD

CA

So,

18

2x−1

=

3x+9

2x+2

=

6x

3x

Now taking

18

2x−1

=

6x

3x

, we have

18

2x−1

or 4x−2=18 or x=5

Therefore, AB=2×5−1=9,

BC=2×5+2=12,CA=3×5=15,

DE=18,EF=3×5+9=24

and FD=6×5=30

Hence,

AB=9cm,BC=12cm,CA=15cm,DE=18cm,EF=24cm and FD=30cm

Similar questions