Question

guys pls help me may god bless who ever will ans this q​

Answer 1

$\large\mathscr \color{white}\colorbox{red}{\colorbox{orange}{\colorbox{yellow}{\colorbox{green}{\colorbox{blue}{\colorbox{indigo}{\colorbox{violet}{\colorbox{black}{\underline {ANSWER}}}}}}}}}$

$\tt\theta = 90\degree \\ \\ \tt let \: A = 8 \: and \: B = 6 \\ \\ \tt{x = \sqrt{ {A}^{2} + {B}^{2} + 2ABcos \theta } }\\ \\ \tt x = \sqrt{ {8}^{2} + {6}^{2} + 2 \times 8 \times 6 \times cos90 \degree} \\ \\ \tt{x = \sqrt{64 + 36 + 2 \times 8 \times 6 \times 0} }\\ \\ \tt{x = \sqrt{64 + 36}} \\ \\ \tt{ x = \sqrt{100} }\\ \\ \\ \tt {\underline{\underline{ x= 10}}}$