Question

guys pls help me to
solve tan38 - cot22 = ?​

Answer 1

LHS

=tan38°-cot22°

=(sin38°/cos38°)-(cos22°/sin22°)

=(sin38°sin22°-cos38°cos22°)/(cos38°)(sin22°)

=-cos(38°+22°)(sec38°)(cosec22°)

=-cos60°cosec22°sec38°

=-½cosec22°sec38°

hope it helps.

pls mark brainliest.

Answer 2

Answer:

$\huge\underline{ \underline{ \purple{your \: \: answer}}}$

Step-by-step explanation:

$\sf\red{tan38° - cot22°} \\ \sf\red{ = > \frac{sin38°}{cos38° } - \frac{cos22°}{sin22°} } \\ \sf\red{ = > \frac{sin38°sin22° - cos22°cos38°}{cos38°sin22°} } \\ \sf\green{we \: know \: thatcos(A + B) = cosAcosB - sinAsinB} \\ \sf\red{ = > \frac{ - cos(60°)}{sin(22°)cos(38°)} } \\ \sf\red{=> \frac{ \frac{-1}{2} }{sin(22°)cos(38°)} } \\ \sf\red{=> \frac{-1}{2}cosec22°sec38° } \\ \large\boxed{ \fcolorbox{pink}{blue}{hope \: it \: help \: you}}$