Question

Guys pls help with this question
a train is travelling at a speed of 54 kmph brakes are applied so as to produce a uniform acceleration of -0.25 ms. Calculate the distance travelled by the train before it comes to rest.
Pls pls pls

Answer 1

Answer:

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your solution is attached with the picture......

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Answer 2

$\large{\underline{\bf{\pink{Answer:-}}}}$

✰ distance travelled by the train = 450m.

$\large{\underline{\bf{\blue{Explanation:-}}}}$

✰ we used the equation v² - u² = 2as

where,

➜⠀⠀⠀v = final velocity

➜⠀⠀⠀u = initial velocity

➜⠀⠀⠀a = acceleration

➜⠀⠀⠀s = distance

$\large{\underline{\bf{\green{Given:-}}}}$

✰ ⠀⠀⠀Inital velocity (u) = 54km/h

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 54×(5/18)

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 15m/s

✰⠀⠀⠀ Final velocity (v) = 0

✰ ⠀⠀⠀Acceleration (a) = -(0.25)

$\large{\underline{\bf{\green{To\:Find:-}}}}$

➜⠀⠀⠀we need to find the distance ⠀⠀⠀⠀⠀⠀travelled by the train.

$\huge{\underline{\bf{\red{Solution:-}}}}$

➩⠀⠀⠀v² - u² = 2as

putting all values in the equation.

we get ,

➩⠀⠀⠀0² - (15)² = 2 × (-0.25)×s

➩⠀⠀⠀-225 = - 0.5s

➩⠀⠀⠀s = 225/0.5

➩⠀⠀⠀s = 450m

So the distance travelled by the train is 450 m.

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