Question

guys pls prove it......

Answer 1

divide by cos 11° in numerator and denominator in RHS
$\frac{ \frac{ \cos(11°) + \sin(11°) }{ \cos(11°) } }{ \frac{ \cos(11°) - \sin(11°) }{ \cos(11°) } } \\ = \frac{1 + \tan(11°) }{1 - \tan(11°) } \\ = \frac{ \tan(45°) + \tan(11°) }{1 - \tan(45°) \tan(11°) } \\ we \: know \: that \: \\ \frac{ \tan(x) + \tan(y) }{1 - \tan(x) \tan(y) } = \tan(x + y) \\ apply \: this \\ \tan(45° + 11°) \\ \tan(56°) \: \: \: \: \:$HENCE PROVE