a force is applied on a body of mass 0.9 kg that is at rest the force is applied for the duration of 5 seconds and as a result the body covers a distance of 250 M find the magnitude of the force
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mass = m = 0.9kg = 9×10^-1kg
intial speed = u = 0m/s
distance = s = 250m
time = 5s
acceleration = a = ?
s = ut + at²/2
s = 2ut+at²/2
2s = 2ut + at²
a = 2s-2ut/t²
a = 2(250)-(2)(0)(5)/(5)²
a = 500-0/25
a = 500/25
a = 20m/s²
F = ma
F = 0.9 × 20
F = 18.N
intial speed = u = 0m/s
distance = s = 250m
time = 5s
acceleration = a = ?
s = ut + at²/2
s = 2ut+at²/2
2s = 2ut + at²
a = 2s-2ut/t²
a = 2(250)-(2)(0)(5)/(5)²
a = 500-0/25
a = 500/25
a = 20m/s²
F = ma
F = 0.9 × 20
F = 18.N
gloryangel:
tq
Will u plz help me like this
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