Guys pls solve quez no.18. ASAP PLS
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it is given that triangle ABC is a right angled triangle right angled at C and D is the mid point of bc .
by applying pythagoras theorem in triangle ABC , we get
AB2=AC2+BC2 =AC2+(2CD)2 (SINCE D IS THE MID POINT OF BC) =AC2+4CD2 =AC2+4(AD2-AC2) ( SINCE IN TRIANGLE ACD WE GET AD2=AC2+CD2) =AC2+4AD2-4AC2 =4AD2-3AC2
THEREFORE , AB2=4AD2-3AC2.
by applying pythagoras theorem in triangle ABC , we get
AB2=AC2+BC2 =AC2+(2CD)2 (SINCE D IS THE MID POINT OF BC) =AC2+4CD2 =AC2+4(AD2-AC2) ( SINCE IN TRIANGLE ACD WE GET AD2=AC2+CD2) =AC2+4AD2-4AC2 =4AD2-3AC2
THEREFORE , AB2=4AD2-3AC2.
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