guys plz answer below 25 th question. tomorrow is my maths exams.. plz
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given AC=3cmAC=3cm
and BC=4cm
∴ABC=5cm
Let CP=ycm
and AP=xcm
CP2+AP2=AC2
=> y2+x2=9y
=> y2=9y−x2
y2+(5−x)2=16y2
y2=16−(5−x)
y2=16−25−x2+10xy2=16−25−x2+10x
9−x2=−9−x2+10x9−x2=−9−x2+10x
18=10x
y2=9−(1.8)2y
=24cm
CD=4.8cm
and BC=4cm
∴ABC=5cm
Let CP=ycm
and AP=xcm
CP2+AP2=AC2
=> y2+x2=9y
=> y2=9y−x2
y2+(5−x)2=16y2
y2=16−(5−x)
y2=16−25−x2+10xy2=16−25−x2+10x
9−x2=−9−x2+10x9−x2=−9−x2+10x
18=10x
y2=9−(1.8)2y
=24cm
CD=4.8cm
hastidDobariya:
thx so much
Answered by
3
Answer:
CD = 4.8 ans...............in short
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