Question

Guys plz Fast..!...,....​

Answer 1

Answer:

In this kind of Question, first we need to first draw the Free-Body Diagram of both the bodies and create the force equations.

For 4 kg Block , we can say :

$F - ( F_{spring} ) = 4a \: ........(1)$

For 2 kg Block , we can say :

$F_{spring} = 2a \: ........(2)$

Adding the 2 Equations, we get :

$F = (2 + 4)a = 6a$

$= > 10 = 6a$

$= > a = \dfrac{10}{6}$

$= > a = \dfrac{5}{3} \:m {s}^{ - 2}$

Putting value of acceleration in 2nd equation , we get :

$\therefore \: F_{spring} = 2a$

$= > \: F_{spring} = 2 \times ( \frac{5}{3} )$

$= > \: F_{spring} = \dfrac{10}{3} \: N$

So final answer :

$\boxed{ \huge{ \bold{ \green{ \: F_{spring} = \dfrac{10}{3} \: N }}}}$

Answer 2

.......

$\tt{\huge{\purple{ ......,.....}}}$

QUESTION :

See the above attachment..

SOLUTION :

See the attachment above.