Question

Guys plz help ne to find this..its urgent ​

Answer 1

Answer:

a) Area of triangle ABC = 1/2 ×base × height

= 1/2 × 4 × 3

= 6 cm^2

b) Area of triangle DEF = 1/2 × base × height

= 1/2 × 4 ×3

= 6 cm^2

Answer 2

Step-by-step explanation:

$\scriptsize(a) \: \: area \: of \: triangle \: = \frac{1}{2} \times base \times height$

height AB = 3cm and base BC = 4cm

$\scriptsize{So, area \: of \: triangle \: ABC = \frac{1}{2} \times 4 \times 3}$

$= \frac{1}{ \cancel2} \times \cancel{12}$

$= 6 \: cm$

(b.)

∵ AP || BR and distance between them is 3 cm

∴ DX = 3 cm

Since the perpendicular from the vertex of the triangle to the base bisects the base.

∴ EX = 2 cm and FX = 2 cm

So , area of triangle DEF = area of triangle DEX + area of triangle DFX

$= \frac{1}{2} \times 2 \times 3 + \frac{1}{2} \times 2 \times 3$

$= \frac{1}{ \cancel2} \times \cancel6 + \frac{1}{\cancel2} \times \cancel6$

$= 3 + 3$

$= 6 \: cm$