Question

Guys plz solve it as soon as possible ..........



Need it urgently.




Plz don't answer if u don't know....

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Answer 1

We can take dot product

so, A.B = |A||B|cosθ           ................(1)

A.B = -1 + 2 + 2= 3

|A| = $\sqrt{1^2+2^2+1^2}$ = $\sqrt[]{6}$

Again |B| = $\sqrt{1^2+1^2+2^2}$ = $\sqrt{6}$

now, substituting all values in the first equation

3 = $\sqrt[]{6}$ x $\sqrt{6}$ x cosθ

$\frac{3}{6}$ = cosθ

$\frac{1}{2}$ = cosθ

=> θ = $cos^-^1$($\frac{1}{2}$ )

=> θ = 60⁰

please mark me brainliest