Guys plzz answer the above ques . Thank you
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2.tan 2A = cot(A-18)
cot (90-2A)=cot(A-18)
90-2A=A-18
-2A-A=-18-90
-3A=-108
minus and minus cancel
A=108/3
A=36
hence proved
cot (90-2A)=cot(A-18)
90-2A=A-18
-2A-A=-18-90
-3A=-108
minus and minus cancel
A=108/3
A=36
hence proved
abcde9:
Thank you !
Answered by
1
Note here i am taking angle as A
Given:4tanA=3
So tanA=3/4
But tanA=P/B
Therefore P=3 and B=4
By pythagorous thoeram
H=5
Now as according to question
sinA=P/H=3/5
cosA=B/H=4/5
Putting values in given equation
Rest of is in photo
Given:4tanA=3
So tanA=3/4
But tanA=P/B
Therefore P=3 and B=4
By pythagorous thoeram
H=5
Now as according to question
sinA=P/H=3/5
cosA=B/H=4/5
Putting values in given equation
Rest of is in photo
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Thanks for helping !!
But you have made a mistake in the third step ( in d pic )
Its -4 +5 so its supposed to give 1
You have added them up
Anyway thanks for helping !
Sorry for that.
The answer will be 13/11
Yeah
Thanks !
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