Question

Guys plzz answer the above ques . Thank you

Answer 1

Its very simple.. Let me help u..
Refer my stepwise solution and ping me for details...
P.S. Q2)The correct question is
tan2A = cot(A-18)

PLZZ MARK AS BRAINLIEST!!

Answer 2

Hi there!

♦ Q.1 :- 4 tanA = 3

tanA = 3/4 = Perpendicular/Base

So,
Perpendicular = 3k
Base = 4k

By Pythagoras Theorem,

H² = P² + B²

H² = (4k)² + (3k)²

H = √16k² + 9k²

H = √25k² = 5k

Now,
4 sinA - cosA + 1 / 4 sinA + cosA - 1

[ 4 × 3k/5k - 4k/5k + 1 ] / [ 4 × 3k/5k + 4k/5k -1 ]

[ 12/5 - 4/5 + 1 ] / [ 12/5 + 4/5 - 1 ]

[ 13/5 ] / [ 11/5 ]

13/5 × 5/ 11

13/11

♦ Q.2 :- tan 2A = cot (A - 18°)

cot (90° - 2A) = cot (A - 18°)

90° - 2A = A - 18°

3A = 90° + 18°

3A = 108°

A = 108/3

A = 36°

Hence,
Value of 'A' is 36°

[ Thank you! for asking the question. ]
Hope it helps!