if x=3 is root of the quadratic equation of xsquare-2k-6 finf tje value of k
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x² - 2k - 6 = 0
(3)² - 2k - 6 = 0
9 - 2k - 6 = 0
2k = 3
k = 3/2 = 1.5
(3)² - 2k - 6 = 0
9 - 2k - 6 = 0
2k = 3
k = 3/2 = 1.5
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