Question

Guys !! So today your questions are ➡

★ First write the IUPAC names of the above given compounds in the picture

★ Answer the following ➡

• Name an acid which furnish three hydronium ions per molecule ( Sulphurous acid / phosphoric acid )

• What do you observe when excess of ammonia is passed through an aqua solution of lead nitrate ? ( With reaction )

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Answer 1

Answer:

The number of carbon atoms in the alkane obtained

by the electrolysis of aqueous solution of sodium

salt of ethanoic acid is

(1) 8

(2) 2

(3) 6

(4) 4

Answer 2

Required Answer:-

Answer - (1)

The IUPAC names of the compounds in the attachment are as follows:

1. Hexanoic acid
2. propanone or propan-1-one
3. Butan-2-ol
4. Hex-2-ene
5. Butan-2-one

Note:-

• I hope, you are aware of the important rules in IUPAC nomenclature.
• You should know the functional groups and how to name the compound according to the functional group attached to which carbon atom.

Answer - (2)

1. Sulphurous acid ($\rm{H_2SO_3}$) and phosphoric acid ($\rm{H_3PO_4}$). Clearly there are 3 atoms of hydrogen in one atom of phosphoric acid. After disassociation, they will combine with 3 molecules to water to form the hydronium ions.

2. When ammonia gas is passed over the lead nitrate, a double displacement reaction takes place and lead hydroxide is formed as the precipitate. The other product is ammonium nitrate.

First ammonia reacts with water to form ammonium hydroxide:

$\rm{NH_3 + H_2O \longrightarrow NH_4OH}$

Then the double displacement reaction:

$\rm{Pb(NO_3)_2 + 2NH_4OH \longrightarrow 2NH_4NO_3 + Pb(OH)_2}$