Question

guys solve it correctly if you want to be a brainliest ​

Answer 1

Explanation:

πR=L

R=L/π

V=-GM/R

=-πGM/L. ( replacing R with L/π)

so correct answer is 1..

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hope my answer will be satisfied to you...

Answer 2

We need to solve this type of questions using integration :

Let's consider an elemental portion on the ring consisting of mass dm. Radius of wire be r

Therefore, πr = l => r = l/π

So the potential at centre because of that mass be dV , we can say that :

$dV = - G \dfrac{dm}{r}$

Integrating on both sides :

$= > \displaystyle \int \: dV = - G \int\dfrac{dm}{r}$

$= > \displaystyle \int \: dV = - G \int\dfrac{dm}{ (\frac{l}{\pi} )}$

$= > \displaystyle \int \: dV = - G\pi \int\dfrac{dm}{ l}$

$= > \displaystyle \int \: dV = - \dfrac{G\pi}{l} \int \: dm$

$= > V = - \dfrac{G\pi}{l} m$

So final answer :

$\boxed{ \red{ \huge{ \bold{ V = - \dfrac{G\pi}{l} m}}}}$