Question

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Answer 1

Answer:

Let first term be a

c.d.of first and second A.Ps be D1 and D2 respectively.

7th term= 23 and 21th term= 125

So,a+6d1= 23

a= 23-6d1 (eq.1)

a+20d2=125

a= 125-20d2 (eq.2)

from eq.1and2 we get,

23-6d1=125-20d2

20d2-6d1= 102

10d2-3d1= 51. (eq.3)

but D1:d2= 1:2

d2=2d1

from eq.3

20d1-3d1=51

17d1=51

D1=3

d2=6

a+18=23

a=5

So,two a.ps are 5,8,11,14......

and 5,11,17,23.....

Answer 2

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