sides BC CA and BA of a triangle ABC are produced to d p q respectively as shown in the figure if angle ACB is equal 100 degree and Angle Q ap is equal to 35 degree find the angles of a triangle
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∠BAC=∠EAF=45∘ (∵ vertically opposite angles )
∠ACB=180∘−∠ACD=180∘−105∘=75∘
∠ABC=180∘−∠BAC−∠ACB=180∘−45∘−75∘=60∘
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