Guys solve this problem
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Solution
Given :-
- 3^x = 9^y = 27^z = 81
Find :-
- Value of x, y & z
Explanation
First we take , first and last part
==> 3^x = 81
==> 3^x = 3 × 3 × 3 × 3
==>3^x = 3⁴
We know,
- if a^m = a^n then, n = m
==> x = 4 .
again, take second and last terms
==> 9^y = 81
==> 9^y = 9 × 9
==> 9^y = 9²
We know,
- if a^m = a^n then, n = m
==> y = 2
Again, take third & last terms
==> 27^z = 81
==> ( 3 × 3 × 3)^z = 3 × 3 × 3 × 3
==> 3^(3z) = 3⁴
We know,
- if a^m = a^n then, n = m
So,
==> 3z = 4
==> z = 4/3
Hence
- Value of x = 4
- Value of y = 2
- Value of z = 4/3
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