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22) Given : (2 , -1) is a solution of the equation
⇒
⇒
∴
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23) Given : in ΔABC , ∠BAC = 64° ; ∠ABC = 50°
We know the sum of the angles in a triangle is 180°
⇒ ∠ABC + ∠ACB + ∠BAC = 180°
⇒ 50° + ∠ACB + 64° = 180°
⇒ ∠ACB = 180° - 114°
⇒ ∠ACB = 66°
∵ Angles B & C are bisected
∠OBC = ∠ABC / 2 = 50°/2
⇒ ∠OBC = 25°
Also, ∠OCB = ∠ACB / 2 = 66°/2
⇒ ∠OCB = 33°
Now in ΔOBC,
∠OBC + ∠OCB + ∠BOC = 180° (∵sum of the interior angles of triangle)
⇒ 25° + 33° + ∠BOC = 180°
⇒ ∠BOC = 180 - 58°
∴ ∠BOC = 122°
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