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In triangle ABD and ADC-
AB=AC[given]
AD=AD[common]
BD=CD[ as angle cbd = angle bcd sides cd=bd as angles opposite to equal sides are equal]
hence triangle ABD= triangle ACD by SSS congruence rule.
angle bad= angle cad [c.p.c.t ]
therefore AD bisects angle bac of triangle abc.
hope it helps you...... thumbs uppp!
AB=AC[given]
AD=AD[common]
BD=CD[ as angle cbd = angle bcd sides cd=bd as angles opposite to equal sides are equal]
hence triangle ABD= triangle ACD by SSS congruence rule.
angle bad= angle cad [c.p.c.t ]
therefore AD bisects angle bac of triangle abc.
hope it helps you...... thumbs uppp!
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