Question

guyz help in this one ,plz give appropriate answer​

Answer 1

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Net resistance between A and B

Here we are starting from A and let the resistances as 1,2,3,4and5 and the 30 ohm resistor=6

In this figure,

resistance 1 is in series

2 and 4 are in parallel

and 3 and 6 are are in parallel

and resistance 5 is also in series.

Net resistance between these two

=10+reciprocal of(1/20+1/20)+reciprocal of(1/10+1/30)+10

=10+10+15+10

=45ohm

The answer of your question is 45ohm

So the net resistance between A and B will be 45ohm.

Answer 2

Answer: 38.75

Explanation:

Let the resistances be named as R1 , R2 , R3 , R4 , R5 and R6 as shown in (Image 1)

Now,

R4 , R6 and R5 are in series combination. If their equivalent resistance is R',(Image 1)

R' = R4 + R6 +R6

R' = 20 + 20 + 10

R' = 50 Ω

Now R' and  R3 are in parallel combination. If their equivalent resistance is R'', (Image 2)

1/R" = 1/R' + 1/R3

1/R'' = 1/50 + 1/30

1/R'' = (3+5)/150

1/R'' = 8/150

R'' = 150/8

R'' = 18.75 Ω

Now R'' , R1 and R2 are in series combination. If  the equivalent resistance is R, (Image 3)

R = R1 +R2 + R''

R = 10 + 10 + 18.75

R = 38.75