guyz please help its urgent
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(I+A)3
=I3+A3+3AI(I+A)
=I3+A3+3A(I+A) {As, A I = A}
=I3+A3+3AI+3A2
=I+A2A+3A+3A2
=I+A.A+3A+3A {As, A2 = A}
=I+A2+6A
=I+A+6A
=I+7A
Hence Proved
=I3+A3+3AI(I+A)
=I3+A3+3A(I+A) {As, A I = A}
=I3+A3+3AI+3A2
=I+A2A+3A+3A2
=I+A.A+3A+3A {As, A2 = A}
=I+A2+6A
=I+A+6A
=I+7A
Hence Proved
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